The reagents that can be used to identify $F e^{3 +}$ is :

K_{4} F e (C N)_{6}

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K C N S

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C H_{3} C O O^{-}

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All of the above

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Solution

The correct option is B All of the above
(i). F(III) ions give deep blue colour with potassium ferrocyanide.
$3 K_{4} [F e (C N)_{6}] + 4 F e C l_{3} \to F e_{4} [F e (C N)_{6}]_{3} prussian blue + 12 K C l$
(ii). Fe(III) ion gives a blood red colouration with thiocyanate ions.
$F e C l_{3} + 3 N H_{4} S C N \to F e (S C N)_{3} red colour + 3 N H_{4} C l$

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