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Nomenclature

The reagents ...

Question

The reagents to carry out the following conversion are

H g S O_{4} / d i l . H_{2} S O_{4}

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B H_{3}; H_{2} O_{2} / N a O H

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O s O_{4}; H I O_{4}

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N a N H_{2} / C H_{3} I; H g S O_{4} / d i l . H_{2} S O_{4}

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Solution

The correct option is D $N a N H_{2} / C H_{3} I; H g S O_{4} / d i l . H_{2} S O_{4}$
(Here, $M e$ means methyl group)

Thus, the correct set of reagent is $N a N H_{2} / C H_{3} I; H g S O_{4} / d i l . H_{2} S O_{4}$

Option D is correct.

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Similar questions

a i r Δ \to

H C l \to

N a_{2} C O_{3} \to

Δ \to

C a (O H)_{2} \to

d i l . H_{2} S O_{4} \to

N a O H \to

H N O_{3} \to

e v a p o r a t e \to

Δ \to

O_{2} + D

B e - C H_{2} - C H_{2} - B r \to H - C \equiv C - H

Z n + d i l . H_{2} S O_{4} \to Z n S O_{4} + H_{2}

Z n + c o n c . H_{2} S O_{4} \to Z n S O_{4} + S O_{2} + H_{2} O

I

I I

C H_{3} - C H = C H - C H_{2} - O ∥ C - C H_{3} \to C H_{3} - C H = C H - C H_{2} - O ∥ C - O H

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