The real number k for which the equation x3+3x+k=0 has two distinct real roots in [0,1]
A
lies between 1 and 2
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B
lies between 2 and 3
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C
lies between -1 and 0
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D
does not exist.
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Solution
The correct option is D does not exist. f(x)=2x3+3x+kf′(x)=6x2+3>0∀xϵR(∵x2>0) ⇒f(x) is strictly increasing function ⇒f(x)=0 has only one real root, so two roots are not possible.