The real order pair (x,y) which satisfies (x4+2xi)−(3x2+yi)=(3−5i)+(1+2yi) is
A
(−2,13)
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B
(2,3)
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C
(−2,3)
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D
(2,13)
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Solution
The correct options are A(−2,13) B(2,3) Given (x4+2xi)−(3x2+yi)=(3−5i)+(1+2yi) ⇒(x4−3x2)+i(2x−3y)=4−5i Equating real and imaginary parts, we get x4−3x2=4⇒x2=4⇒x=±2 and 2x−3y=−5 ⇒y=3,13 Hence (x,y)≡(2,3),(−2,13)