The rear view mirror of a car is a plane mirror. A driver is reversing his car at a speed of 2 $\frac{m}{s}$ . The driver sees in his rear view mirror the image of the truck parked behind his car. The speed at which the image of the truck appears to approach the driver will be?

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Solution

The speed of the car is 2 $\frac{m}{s}$ which means the car is approaching the truck with a speed of 2 $\frac{m}{s}$ . The distance between the image of truck and car will decrease at a double rate. This is because the image of the truck will travel a distance twice the distance travelled by the car in equal time. Hence, the image of the truck will appear to approach the driver with the speed of 2 $\times$ 2 = 4 $\frac{m}{s}$ .

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The rear view mirror of a car is a plane mirror. A driver is reversing his car at a speed of 2 m/s. The driver sees in his rear view mirror the image of truck parked behind his car. The speed at which the image of the truck appears to approach the driver will be

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(iii) 4 m/s

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Question 13
The rear view mirror of a car is a plane mirror. A driver is reversing his car at a speed of 2 m/s. The driver sees in his rear view mirror the image of a truck parked behind his car. The speed at which the image of the truck appears to approach the driver will be
(i) 1 m/s
(ii) 2 m/s
(iii) 4 m/s
(iv) 8 m/s

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The rear view mirror of a car is a plane mirror. A driver is reversing his car at a speed of 2 ms. The driver sees in his rear view mirror the image of the truck parked behind his car. The speed at which the image of the truck appears to approach the driver will be?

The rear view mirror of a car is a plane mirror. A driver is reversing his car at a speed of 2 $\frac{m}{s}$ . The driver sees in his rear view mirror the image of the truck parked behind his car. The speed at which the image of the truck appears to approach the driver will be?