The reciprocal matrix of ⎡⎢⎣10201−1121⎤⎥⎦ is
A
⎡⎢⎣−3−42−11−112−1⎤⎥⎦
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B
⎡⎢⎣34−21−11−1−21⎤⎥⎦
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C
⎡⎢⎣−3−11−4122−1−1⎤⎥⎦
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D
⎡⎢⎣34−2−1−11−1−21⎤⎥⎦
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Solution
The correct option is C⎡⎢⎣34−2−1−11−1−21⎤⎥⎦ Given matrix is ⎡⎢⎣10201−1121⎤⎥⎦ |A|=1 cofactor matrix is ⎡⎢⎣3−1−14−1−2−211⎤⎥⎦ adjA=⎡⎢⎣34−2−1−11−1−21⎤⎥⎦ ∴A−1=⎡⎢⎣34−2−1−11−1−21⎤⎥⎦