Question

The rectangle below has an area of $32x^3$ square meters and a length of $4x^2$ square meters.


What is the width of the rectangle?

• A. $4x$
• B. $4x^2$
• C. $x^4$
• D. $2x^2$

Answer 1

The correct option is A $4x$

$\underset{–}{\text{Given:}}$


Area of the rectangle $=32x^2$
Length of the rectangle $=8x^2$

$\underset{–}{\text{Need to Find:}}$ Width of the rectangle

As given in the hint,
Area of a rectangle $=$ Length $\times$ Width

$\Rightarrow 32x^3=8x^2$ $\times$ Width

Dividing both side by $8x^2,$ we get

$\Rightarrow \frac{32x^3}{8x^2}=\frac{8x^2\times \text{Width}}{8x^2}$

$\Rightarrow (\frac{32}{8})x^{(3-2)}=$ Width

$\Rightarrow (\frac{8\times 4}{8})x=$ Width

$\Rightarrow 4x=$ Width

$\therefore$ The width of the rectangle is $4x.$

Hence, option (a.) is the correct choice.