The rectangular field is $112 m$ long and $62 m$ broad. A cubical tank of edge $6 m$ is dug at each of the four corner of the field and the earth so removed is evenly spread on the remaining field. Find the rise in level.

11.74 c m

(approx.)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12.72 c m

(approx.)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

17.28 c m

(approx.)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

19.75 c m

(approx.)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $17.28 c m$ (approx.)
Length of the rectangular field $= 112$ m
Breadth of the field $= 62$ m
Edge of the cubical tank $= 6$ m
Volume of the cube $= 6 \times 6 \times 6$ $= 216 m^{3}$
Volume of $4$ cubical tanks $= 4 \times 216 m^{3}$ $= 864 m^{3}$
Thus, the length and breath is reduced by $6 + 6 = 12 c m$ .
Thus, the new length $l = 112 - 12 = 100 c m$
and the new breath $b = 62 - 12 = 50 c m$
Let rise in level $= h$
$∴ l \times b \times h = 864$
$=> 100 \times 50 \times h = 864$
$=> h = \frac{864}{5000}$
$=> h = 0.1728 m$
$=> h = 17.28 c m$

Suggest Corrections

Similar questions

A rectangular field is 70 m long and 60 in broad. A well of dimensions $14 m \times 8 m \times 6 m$ is dug outside the field and the earth dug-out from this well is spread evenly on the field. How much will the earth level rise?

A field is $80 m$ long and $50 m$ broad. In one corner of field, a pit which is $10 m$ long, $7.5 m$ broad and $8 m$ deep has been dug out. The earth taken out of it is evenly spread over the remaining part of field. Find the rise in level of field.

Q. A rectangular field is

70 m

long and

60 m

broad. A well of dimensions

14 m \times 5 m \times 6 m

is dug outside the field and the earth dugout from this well is spread evenly in the field. How much will the earth level rise?

Q. A field is 120 m long and 50 m broad. A tank 24 m long, 10 m broad and 6 m deep is dug any where in the field and the earth taken out of the tank is evenly spread over the remaining part of the field. Find the rise in level of the field in cm.

A rectangular tank of dimensions $24 m \times 12 m \times 8 m$ is dug inside a rectangular field $600 m$ long and $200 m$ broad. The earth take out is evenly spread over the field. By how much will rise the level of the field rise?

Join BYJU'S Learning Program

The rectangular field is 112m long and 62m broad. A cubical tank of edge 6m is dug at each of the four corner of the field and the earth so removed is evenly spread on the remaining field. Find the rise in level.

The rectangular field is $112 m$ long and $62 m$ broad. A cubical tank of edge $6 m$ is dug at each of the four corner of the field and the earth so removed is evenly spread on the remaining field. Find the rise in level.