Question

The reduced bearing of a 10 m long line is N ${30}^{\circ }$ E. The departure of the line is

• A. 10.00 m
• B. 8.66 m
• C. 7.52 m
• D. 5.00 m

Answer 1

The correct option is D 5.00 m

$AB=10m$


Departure $=AB\sin {30}^{\circ }$
$=10\times \frac{1}{2}=5.00m$