CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Direction Cosines of Axes

The reduced b...

Question

The reduced bearing of a 5 m long line is N $60^{o} E$ , The latitude of the line is

A

5 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

10 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

2.5 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

4.33 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 2.5 m

$L = 5 c o s 60^{o}$
$= 2.5 m$

Suggest Corrections

thumbs-up

1

Similar questions

Q. The reduced bearing of a 10 m long line is N

30^{\circ}

E. The departure of the line is

Q. The latitude and departure of a line AB are +78 m and -45.1 m, respectively. The whole circle bearing of the line AB is:

Q. The magnetic bearing of a line AB is S

45^{\circ}

E and the declination is

5^{\circ}

West. The true bearing of the line AB is

Q. The magnetic bearing of a line is

50^{\circ} 32^{'} .

If the magnetic declination is

6^{\circ} 02^{'}

West, then the true bearing of the line is

Q. The fore bearing of line AB is

150^{\circ}

and the angle ABC is

124^{\circ}

then the fore bearing of line BC is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Direction Cosines and Direction Ratios

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Direction Cosines of Axes

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon