Question

The reduced form of $\frac{6x^2-54}{x^2+7x+12}$ is .

• A. $\frac{6(x-3)}{(x+4)}$
• B. $\frac{6(x+3)}{(x+4)}$
• C. $\frac{(x-3)}{(x+4)}$
• D. $\frac{(x+3)}{(x+4)}$

Answer 1

The correct option is A $\frac{6(x-3)}{(x+4)}$

$\frac{6x^2-54}{x^2+7x+12}$
=$\frac{6(x^2-9)}{(x+3)(x+4)}$
=$\frac{6(x^2-3^2)}{(x+3)(x+4)}$
=$\frac{6(x+3)(x-3)}{(x+3)(x+4)}$
=$\frac{6(x-3)}{(x+4)}$