The reduced form of the algebraic expression 2a2-b2-a-b is

2(a^2 b^2)/(a + b) We know that, a^2 b^2 = (a + b)(a b) 2(a^2 b^2)/(a + b) = 2(a+b)(a b)/a+b So, the term (a+b) from both numerator and denominator shou ...

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Standard VIII

Mathematics

Multiplication of Binomials

The reduced f...

Question

The reduced form of the algebraic expression $\frac{2 (a^{2} - b^{2})}{(a + b)}$ is ___

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Solution

$\frac{2 (a^{2} - b^{2})}{(a + b)}$

We know that, $a^{2} - b^{2} = (a + b) (a - b)$

$\frac{2 (a^{2} - b^{2})}{(a + b)}$ = $\frac{2 (a + b) (a - b)}{a + b}$

So, the term (a+b) from both numerator and denominator should get canceled.

The shortest form is 2(a-b)

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The reduced form of the algebraic expression is: $\frac{2 (a^{2} - b^{2})}{(a + b)}$ is ___

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The reduced form of the algebraic expression 2(a2 − b2)(a + b) is ___

2(a2 − b2)(a + b) We know that, a2 − b2 = (a + b)(a − b) 2(a2 − b2)(a + b) = 2(a+b)(a−b)a+b So, the term (a+b) from both numerator and denominator should get canceled. The shortest form is 2(a-b)

The reduced form of the algebraic expression $\frac{2 (a^{2} - b^{2})}{(a + b)}$ is ___

$\frac{2 (a^{2} - b^{2})}{(a + b)}$

We know that, $a^{2} - b^{2} = (a + b) (a - b)$

$\frac{2 (a^{2} - b^{2})}{(a + b)}$ = $\frac{2 (a + b) (a - b)}{a + b}$

So, the term (a+b) from both numerator and denominator should get canceled.

The shortest form is 2(a-b)