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Why Com Is an Important Point

The reduced m...

Question

The reduced mass of two particles having masses $4 m$ and $2 m$ is

A

2 m

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B

3 m

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C

\frac{4 m}{3}

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D

\frac{m}{2}

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Solution

The correct option is C $\frac{4 m}{3}$
Given that,
$m_{1} = 4 m$
$m_{2} = 2 m$
Reduced mass of the two particles $= μ = \frac{m_{1} m_{2}}{m_{1} + m_{2}}$
Substitute the value in the equation -
$μ = \frac{4 m \times 2 m}{4 m + 2 m}$
$= \frac{8 m^{2}}{6 m}$
$= \frac{4 m}{3}$

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