The reducing agent in the following reaction is-Pb s - Cu 2- aq - Pb 2- aq - Cu s A- Pb 2- aq B- Cu 2- aqC- Pb sD- Cu s

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Oxidation and Reduction

The reducing ...

Question

The reducing agent in the following reaction is:
Pb(s) + Cu²⁺(aq) → Pb²⁺ (aq) + Cu(s)

Pb²⁺ (aq)

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Cu²⁺ (aq)

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Pb (s)

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Cu (s)

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Solution

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The reducing agent in the following reaction is:
Pb(s) + Cu²⁺(aq) → Pb²⁺ (aq) + Cu(s)

What is the oxidizing agent in the following redox reaction?

$Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)$

C u^{2 +} (a q) + Z n (s) \to Z n^{2 +} (a q) + C u (s)

C u_{(s)} \to C u_{(a q)}^{2 +} + 2 e^{-}; E^{o} = - 0.325 V

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}; E^{o} = 0.50 V

E^{o}

2 C u_{(a q)}^{+} \to C u_{(a q)}^{2 +} + C u_{(s)}

F e

A g^{+} (a q) + e^{-} - > A g (s) E^{\circ} = + 0.80 V

C u^{2 +} (a q) + 2 e^{-} - - > C u (s) E^{\circ} = + 0.34 V

P b^{2 +} (a q) + 2 e^{-} - - > P b (s) E^{\circ} = - 0.13 V

F e^{2 +} (a q) + 2 e^{-} - - > F e (s) E^{\circ} = - 0.44 V

A l^{3 +} (a q) + 3 e^{-} - - > A l (s) E^{\circ} = - 1.66 V

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