Question

The reduction factor of a tangent galvanometer may be defined as the current passing through it to produce a deflection of :

• A. ${90}^0$
• B. ${45}^0$
• C. ${30}^0$
• D. ${60}^0$

Answer 1

Answer: (B)

${45}^0$

$I=Ktan\theta$, where K is the reduction factor and $\theta$ is the deflection.

=>$K=\frac{I}{tan\theta }$

=> $K=I$ for $\theta ={45}^{\circ }$

So reduction factor will be equal to current passing through galvanometer to produce a deflection of ${45}^{\circ }$