The reduction of 4octyne with H2 in the presence of Pd/CaCO3 quinoline gives:
A
trans-4-octene
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B
cis-4-octene
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C
a mixture of cis and trans-4-octene
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D
a completely reduced product C8H18
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Solution
The correct option is A cis-4-octene The reduction of 4-octyne with H2 in the presence of Pd/CaCO3 quinoline gives cis-4-octene. The carbon carbon tripple bond is selectively reduced to C=C double bond. The product is cis alkene.