The reduction of peroxydisulphate ion by I– ion is expressed by S2O2−8+3I−→2SO2−4+I−3
If the rate of disappearance of I– is 9/2×10–3mol/L−1 s−1, what is the rate of formation of SO2−4 during the same time?
A
10−3mol/L−1 s−1
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B
2×10−3mol L−1 s−1
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C
3×10−3mol L−1 s−1
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D
4×10−3mol L−1 s−1
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Solution
The correct option is C3×10−3mol L−1 s−1 Reduction reaction of peroxydisulphateion: S2O2−8+3I−→2SO2−4+I−3 ∴−d[S2O8]2−dt=−13d[I−]dt=12d[SO2−4]dt=d[I−3]dt
So; −13d[I−]dt=12d[SO2−4]dt 13×92×10−3=12d[SO2−4]dt d[SO2−4]dt=3×10−3mol L−1 s−1
Therefore the rate of appearance of SO2−4 is 3×10−3mol L−1 s−1