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Question

The reduction of peroxydisulphate ion by I ion is expressed by S2O28+3I2SO24+I3
If the rate of disappearance of I is 9/2×103 mol/L1 s1, what is the rate of formation of SO24 during the same time?

A
103 mol/L1 s1
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B
2×103 mol L1 s1
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C
3×103 mol L1 s1
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D
4×103 mol L1 s1
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Solution

The correct option is C 3×103 mol L1 s1
Reduction reaction of peroxydisulphateion:
S2O28+3I2SO24+I3
d[S2O8]2dt=13d[I]dt=12d[SO24]dt=d[I3]dt
So; 13d[I]dt=12d[SO24]dt
13×92×103=12d[SO24]dt
d[SO24]dt=3×103 mol L1 s1
Therefore the rate of appearance of SO24 is 3×103 mol L1 s1

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