Question

The reduction potential of hydrogen electrode at $pH=10$ is:

• A. -0.059 V
• B. -0.59 V
• C. 0.59 V
• D. 0.0 V

Answer 1

Answer: (B)

-0.59 V

Reduction potential of hydrogen electrode is determined as follows:
$E=-0.0591\times pH$ ( at ${25}^{o}C$ )
So, $E=-0.0591\times 10$
$E=-0.59V$.