The reduction potential of hydrogen electrode $(P_{H_{2}} = 1 a t m s : [H^{'}] = 0.1 M]$ at $25^{\circ} C$ will be -

0.00

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- 0.059

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0.118

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0.059

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Solution

The correct option is B $- 0.059$

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Similar questions

The Oxidation potential of hydrogen electrode at $P^{H} = 10$ and $P_{H_{2}}$ at 1atm is :

How much will be the reduction potential of a hydrogen Electrode change when its solution initially at pH = 0 Is neutralized to pH = 7?

p H = 3

25^{\circ} C

\frac{2.303 R T}{F}

0.059 V

p H

0.059 V

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