Question

The reduction potential of hydrogen electrode when placed in a buffer solution is found to be - 0.413 V. The pH of the buffer is ?

Answer 1

$E=E^o-\frac{RT}{nF}\log \left[H^{+}\right]$

$=E_o-\frac{RT}{nF}pH$

$\Rightarrow -0.413=0-\frac{0.0591}{1}\times pH$

$\Rightarrow pH=\frac{0.413}{0.0591}=6.98$

$\Rightarrow pH=6.98$ .