The reduction potential values of $M, N$ and $O$ are $+ 2.46, - 1.13$ and $- 3.13 V$ respectively.

Which of the following order is correct regarding their reducing property?

O > N > M

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O > M > N

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M > N > O

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M > O > N

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Solution

The correct option is A $O > N > M$
The electrode which has more reduction potential is a good oxidizing agent and has least reducing power.

The electrode which has less reduction potential,it has more reducing power.

Reducing property is the tendency to donate electrons. Since O has the lowest reduction potential it will have the highest reducing property. Similarly with N and M.

Hence,option A is correct.

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Similar questions

The reduction potential values of M, N and O are +2.46, -1.13 and -3.13 V respectively. Which of the following order is correct regarding their reducing property?

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The reduction potential values of M,N and O are +2.46,−1.13 and −3.13V respectively. Which of the following order is correct regarding their reducing property?

The reduction potential values of $M, N$ and $O$ are $+ 2.46, - 1.13$ and $- 3.13 V$ respectively.

Which of the following order is correct regarding their reducing property?