The reflection of the point (4, -13) about the line 5x+y+6=0 is
(-1, -14)
Let the reflection point be A (h, k)
Now, the mid point of the line joining (h, k) and (4, -13) will lie on the line 5x+y+6=0
∴ 5(h+42)+k−132+6=0
⇒ 5h+20+k−13+12=0
⇒ 5h+k+19=0 ...(i)
Now, the slope of the line joining points (h, k) and (4, -13) are perpendicular to the line 5x+y+6=0
Slope of the line =−5
Slope of the joining by points (h, k) and (4, -13)
k+13h−4
∴ k+13h−4(−5)=−1
⇒ 5k−h+69=0 ...(ii)
Solving (i) and (ii), we get
h=−1 and k=−14
Hence, the correct answer is option (a).