The refracting angle of a prism 60o.The refractive index of the material of the prism is √73. The limiting angle of incidence of a ray that will be transmitted through the prism in this case will be :
A
300
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B
45o
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C
40o
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D
50o
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Solution
The correct option is B300 Given A=60∘,μ=√73 we know that γ1+r2=A⇒r1+r2=60∘
Snell's law at first refraction sini=μsinγ1Sinγ1=√37sini Snell's law at second refraction