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Question

The refracting angle of a prism 60o.The refractive index of the material of the prism is 73. The limiting angle of incidence of a ray that will be transmitted through the prism in this case will be :

A
300
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B
45o
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C
40o
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D
50o
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Solution

The correct option is B 300
Given A=60,μ=73 we know that γ1+r2=Ar1+r2=60
Snell's law at first refraction sini=μsinγ1Sinγ1=37sini Snell's law at second refraction
μsinr2=1sinr2=37r2=sin1(37)r2=40.89r1=19.1066

Sinr1=0.327sini=73sinr1sini=1/2i=30

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