Question

The refractive index ($\mu$) of glass is found to have the values $1.49,1.50,1.52,1.54and1.48$. Calculate absolute error is each measurement.

• A. $\Delta n_5=1.51-1.48=+0.03$
• B. $\Delta n_4=1.51-1.54=-0.03$
• C. $\Delta n_3=1.51-1.52=-0.01$
• D. All of these

Answer 1

Answer: (D)

All of these

Mean =(1.49+1.50+1.52+1.54 +1.48)/5=1.506=1.51

Absolute error for each,

$\Delta n_1=1.51-1.49=0.02$

$\Delta n_2=1.51-1.50=-0.01$

$\Delta n_3=1.51-1.52=-0.01$

$\Delta n_4=1.51-1.54=-0.03$

$\Delta n_5=1.51-1.48=+0.03$