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Lens Maker's Formula

The refractiv...

Question

The refractive index of a converging lens is $1.4$ . What will be the focal length of this lens if it is placed in a medium of same refractive index? Assume the radii of curvature of the faces of lens are $R_{1}$ and $R_{2}$ respectively.

Zero

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\frac{R_{1} R_{2}}{R_{1} - R_{2}}

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Infinite

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1

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Solution

The correct option is C Infinite
As per Lens maker's formula:
$\frac{1}{f} = [\frac{n_{2}}{n_{1}} - 1] [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$
Since Refrcative indexes, $n_{1}$ and $n_{2}$ are equal.
$\frac{1}{f} = 0$
$\Rightarrow f \to \infty$

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