The refractive index of glass is $1.520$ for red light and $1.525$ for blue light. Let $D_{1}$ and $D_{2}$ be angles of minium deviation for red and blue light respectively in a prism of this glass. Then,

D_{1} < D_{2}

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D_{1} = D_{2}

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D_{1}

can be less than or greater than

D_{2}

depending upon the angle of prism

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D_{1} > D_{2}

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Solution

The correct option is A $D_{1} < D_{2}$
Angle of minimum deviation, $D = (n - 1) A$
where, $n$ is the refractive index of glass
For Red light : $n = 1.520$
$∴$ $D_{1} = (1.520 - 1) A = 0.52 A$

For blue light : $n = 1.525$
$∴$ $D_{2} = (1.525 - 1) A = 0.525 A$

$∴$ $\frac{D_{2}}{D_{1}} = \frac{0.525}{0.52} = 1.0096$

$⟹$ $D_{2} > D_{1}$

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The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1 and D2 be angles of minium deviation for red and blue light respectively in a prism of this glass. Then,

The correct option is A D1<D2Angle of minimum deviation, D=(n−1)A where, n is the refractive index of glassFor Red light : n=1.520∴ D1=(1.520−1)A=0.52AFor blue light : n=1.525∴ D2=(1.525−1)A=0.525A∴ D2D1=0.5250.52=1.0096 ⟹ D2>D1

The refractive index of glass is $1.520$ for red light and $1.525$ for blue light. Let $D_{1}$ and $D_{2}$ be angles of minium deviation for red and blue light respectively in a prism of this glass. Then,