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Physics

Refraction of Light through a Prism

The refractiv...

Question

The refractive index of glass is $1.520$ for red light and $1.525$ for blue light. Let $D_{1}$ and $D_{2}$ be an of minimum deviation for red and blue light respectively in a prism of this glass. Then

D_{1} > D_{2}

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D_{1} < D_{2}

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D_{1} = D_{2}

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D_{1}

can be less than or greater than depending upon the angle of prism.

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Solution

The correct option is B $D_{1} < D_{2}$
A prism follows $μ = \frac{s i n (\frac{A + D}{2})}{s i n (\frac{A}{2})}$

where $A$ is the angle of prism.

Clearly, greater the refractive index $μ$ , greater the angle of deviation $D$ .

Hence $μ_{b l u e} > μ_{r e d}$

$⟹ D_{2} > D_{1}$

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The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1 and D2 be an of minimum deviation for red and blue light respectively in a prism of this glass. Then

The correct option is B D1<D2A prism follows μ=sin(A+D2)sin(A2)where A is the angle of prism.Clearly, greater the refractive index μ, greater the angle of deviation D.Hence μblue>μred⟹D2>D1

The refractive index of glass is $1.520$ for red light and $1.525$ for blue light. Let $D_{1}$ and $D_{2}$ be an of minimum deviation for red and blue light respectively in a prism of this glass. Then

The correct option is B $D_{1} < D_{2}$
A prism follows $μ = \frac{s i n (\frac{A + D}{2})}{s i n (\frac{A}{2})}$

where $A$ is the angle of prism.

Clearly, greater the refractive index $μ$ , greater the angle of deviation $D$ .

Hence $μ_{b l u e} > μ_{r e d}$

$⟹ D_{2} > D_{1}$