The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let $D_{1}$ and $D_{2}$ be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then :

D_{1}

can be less than or greater than

D_{2}

depending upon the angle of prism

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D_{1} > D_{2}

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D_{1} < D_{2}

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D_{1} = D_{2}

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Solution

The correct option is C $D_{1} < D_{2}$
We have angle of minimum deviation,

$D = (μ - 1) A$

Since $μ_{b l u e} > μ_{r e d}$ , $D_{2} > D_{1}$

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The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1 and D2 be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then :

The correct option is C D1<D2We have angle of minimum deviation, D=(μ−1)ASince μblue>μred, D2>D1

The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let $D_{1}$ and $D_{2}$ be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then :

The correct option is C $D_{1} < D_{2}$
We have angle of minimum deviation,

$D = (μ - 1) A$

Since $μ_{b l u e} > μ_{r e d}$ , $D_{2} > D_{1}$