The refractive index of glass is $1.520$ for red light and $1.525$ for blue light. Let $D_{1}$ and $D_{2}$ be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then

$D_{1} > D_{2}$
$D_{1} = D_{2}$
$D_{1} < D_{2}$

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Solution

The correct option is C
$D_{1} < D_{2}$

Explanation for the correct option
Step 1: Given
Refractive index of glass for red light $μ_{r e d}$ = $1.520$
Refractive index of glass for blue light $μ_{b l u e}$ = $1.525$
Angles of minimum deviation for red = $D_{1}$
angles of minimum deviation for blue = $D_{2}$
Step 2: Formula
Angle of minimum deviation is given by
$D = (μ - 1) A$ where $A$ is angle of prism.
Step 3: Compare the refractive index of red and blue
As we know that $D = (μ - 1) A$ , where $D =$ minimum deviation , $μ =$ refractive index
Therefore, $D \propto μ$
Since, $μ_{r e d} < μ_{b l u e}$
so, $D_{1} < D_{2}$
Hence, option C is correct.

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