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Question

The region between X = 0 and X = Lm is filled with uniform steady magnetic field 2T \hat{k}. A particle of mass 2 kg, positive charge 1C and velocity 2(m/s)\hat{i} travels along x-axis and enters the region of the magnetic field (neglect gravity). Find the value of L if the particle emerges from the region of magnetic field with its final velocity at an angle 30^{\circ} to its initial velocity.

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Solution

sin 30=Lr

12=L(mv0qB)

L = mv0qB=2×22×1×2=1m L = 1

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