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Standard XII

Physics

Introduction

The region be...

Question

The region between X = 0 and X = Lm is filled with uniform steady magnetic field 2T \hat{k}. A particle of mass 2 kg, positive charge 1C and velocity 2(m/s)\hat{i} travels along x-axis and enters the region of the magnetic field (neglect gravity). Find the value of L if the particle emerges from the region of magnetic field with its final velocity at an angle 30^{\circ} to its initial velocity.

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Solution

$s i n 30^{\circ} = \frac{L}{r}$

$\frac{1}{2} = \frac{L}{(\frac{m v_{0}}{q B})}$

L = $\frac{m v_{0}}{q B} = \frac{2 \times 2}{2 \times 1 \times 2} = 1 m ∴$ L = 1

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sin 30∘=Lr 12=L(mv0qB) L = mv0qB=2×22×1×2=1m∴ L = 1

$s i n 30^{\circ} = \frac{L}{r}$

$\frac{1}{2} = \frac{L}{(\frac{m v_{0}}{q B})}$

L = $\frac{m v_{0}}{q B} = \frac{2 \times 2}{2 \times 1 \times 2} = 1 m ∴$ L = 1