The correct option is C interior and boundary of an ellipse
We have, |z−1|+|z+1|≤4
⇒√(x−1)2+y2+√(x+1)2+y2≤4
where z=x+iy
⇒A+B≤4
where,A=√(x−1)2+y2andB=....(i)√(x+1)2+y2
But [(x−1)2+y2]−[(x−1)2+y2≤−x]
i.e,A2−B2=−4x.......(ii)
Dividing Eqs. (ii) by (i), we get
√(x−1)2+y2−√(x+1)2+y2≤−x
⇒2√(x+1)2+y2≤4−x
3x2+4y2≤12 [squaring and simplifying]
or, x24+y23≤1
which represents the interior and boundary of the ellipse.