The relation 3t=√3x+6 describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is
3t=√3x+6⇒ 3x=(3t−6)2
⇒ x=3t2−12t+12
v=dxdt=6t-12, for v=0, t=2sec
x=3(2)2−12×2+12=0