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Question

The relation 3t=3x+6 describes the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero, is

A
24 metres
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B
12 metres
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C
5 metres
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D
Zero
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Solution

The correct option is D Zero

3t=3x+6 3x=(3t6)2

x=3t212t+12

v=dxdt=6t-12, for v=0, t=2sec

x=3(2)212×2+12=0


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