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Standard X

Physics

Magnetic Flux and Magnetic Flux Density

The relation ...

Question

The relation between $[E]$ and $[B]$ is

[E] = [B] [L] [T]

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[E] = [B] [L]^{- 1} [T]

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[E] = [B] [L] [T]^{- 1}

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[E] = [B] [L]^{- 1} [T]^{- 1}

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Solution

The correct option is D $[E] = [B] [L] [T]^{- 1}$
We have $\frac{E}{C} = B$
$∴ [B] = \frac{[E]}{[C]} = \frac{[E]}{[L] [T]^{- 1}} = [E] [L]^{- 1} [T]^{1}$
$\Rightarrow [E] = [B] [L] [T]^{- 1}$

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Similar questions

Write the dimensions of a × b in the relation $E = \frac{b - x^{2}}{a t}$ , where E is the energy, x is the displacement and t is time.

Q. PARAGRAPH
In electromagnetic theory, the electric and magnetic phenomena are related to each other. Therefore, the dimensions of electric and magnetic quantities must also be related to each other. In the questions below,

[E]

and [𝐵] stand for dimensions of electric and magnetic fields respectively, while

[ε_{0}]

and

[μ_{0}]

stand for dimensions of the permittivity and permeability of free space respectively.

[L]

and

[T]

are dimensions of length and time respectively. All the quantities are given in SI units.

The relation between [𝐸] and [𝐵] is

Q. (1) B A T
(2) D E A R
(3) L E V E L
(4) M O O N

Q. Write the dimensions of

(a \times b)

in the relation

E = \frac{b - x^{2}}{a t}

, where

E

is the energy,

x

is the displacement and

t

is time.

The option with the values of L that satisfying the equation $\frac{\int_{0}^{4 π} e^{t} (s i n^{6} a t + c o s^{4} a t) d t}{\int_{0}^{π} e^{t} (s i n^{6} a t + c o s^{4} a t) d t} = L,$ is

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The relation between [E] and [B] is

The correct option is D [E]=[B][L][T]−1We have EC=B∴[B]=[E][C]=[E][L][T]−1=[E][L]−1[T]1⇒[E]=[B][L][T]−1

The relation between $[E]$ and $[B]$ is

The correct option is D $[E] = [B] [L] [T]^{- 1}$
We have $\frac{E}{C} = B$
$∴ [B] = \frac{[E]}{[C]} = \frac{[E]}{[L] [T]^{- 1}} = [E] [L]^{- 1} [T]^{1}$
$\Rightarrow [E] = [B] [L] [T]^{- 1}$