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Mechanism of Adsorption

The relation ...

Question

The relation between equilibrium constant $K_{p}$ and $K_{c}$ is

K_{c} = K_{p} (R T)^{Δ n}

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K_{p} = K_{c} (R T)^{Δ n}

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K_{p} = (\frac{K_{c}}{R T})^{Δ n}

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K_{p} - K_{c} = (R T)^{Δ n}

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Solution

The correct option is B $K_{p} = K_{c} (R T)^{Δ n}$
Relation between Kp and Kc is $K_{p} = K_{c} (R T)^{Δ n}$

Hence B is correct option

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Similar questions

The relation between equilibrium constant $K_{P}$ and $K_{C}$ is

K_{p}

K_{c}

K_{p} = K_{c} {(R T)}^{Δ n}

K_{p}

K_{c}

K_{p}

K_{c}

K_{p} = K_{c} (R T)^{Δ n}

\frac{K_{p}}{K_{c}} = {(R T)}^{Δ n}

300 K

\frac{K_{p}}{K_{c}} = 14941.5

Δ n

l o g \frac{K_{p}}{K_{c}} = 4.17

l o g (24.93) = 1.39

K_{p}

K_{c}

K_{p} = K_{c} (R T)^{Δ n}

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