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Direct Method of Finding Mean

The relation ...

Question

The relation between mean, mode and median is
(a) mode = (3 × mean) − (2 × median)
(b) mode = (3 × median) − (2 × mean)
(c) mode = (3 × mean) − (2 × mode)
(d) mode = (3 × median) − (2 × mode)

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Solution

(b) $mode = (3 \times median) - (2 \times mean)$

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The relation between mean,mode and median is

(a) $m o d e = (3 \times m e a n) - (2 \times m e d i a n)$

(b) $m o d e = (3 \times m e d i a n) - (2 \times m e a n)$

(c) $m e d i a n = (3 \times m e a n) - (2 \times m o d e)$

(d) $m e a n = (3 \times m e d i a n) - (2 \times m o d e)$

Q. The empirical relation between mean, mode and median is

(a) Mode = 3 Median − 2 Mean

(b) Mode = 2 Median − 3 Mean

(c) Median = 3 Mode − 2 Mean

(d) Mean = 3 Median − 2 Mode

Q. For a frequency distribution, mean, median and mode are connected by the relation

(a) Mode = 3 Mean − 2 Median
(b) Mode = 2 Median − 3 Mean
(c) Mode = 3 Median − 2 Mean
(d) Mode = 3 Median + 2 Mean

Q. The relationship between mean, median and mode for a moderately skewed distribution is

(a) Mode = 2 Median − 3 Mean
(b) Mode = Median − 2 Mean
(c) Mode = 2 Median − Mean
(d) Mode = 3 Median −2 Mean

Q. Which of the following is correct?

(a) Mode = 2 Median − 3 Mean (b) Mode = 3 Median − Mean
(c) Mode − Mean = 3(Median − Mean) (d) Mode − Median = Median − Mean

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