The relation between momentum (P), mass (m), Kinetic energy (KE) and velocity (V) of a body is :

P V = 2 K E

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K E = \frac{P^{2}}{2 m}

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P^{2} = 2 m K E

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All of the above

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Solution

The correct option is D All of the above
$P = M V K . E = \frac{1}{2} M V^{2} P V = M V^{2} a) P V = 2 K . E b) K . E = \frac{1}{2} P . \frac{P}{M} \Rightarrow \frac{P^{2}}{2 M} P^{2} = 2 M K . E$
If $M_{1} = M_{2} \frac{1}{2} M_{1} V_{1}^{2} = M_{2} \frac{V_{1}^{2}}{2} K E_{1} . M_{2} V_{2} = \frac{1}{2} M_{2}^{2} V_{2} \frac{V_{1}^{2}}{2}$
All the statements are true answered is $D$

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The relation between momentum (P), mass (m), Kinetic energy (KE) and velocity (V) of a body is :

The correct option is D All of the aboveP=MVK.E=12MV2PV=MV2a)PV=2K.Eb)K.E=12P.PM⇒P22MP2=2MK.EIf M1=M212M1V21=M2V212KE1.M2V2=12M22V2V212All the statements are true answered is D