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Question

The relation between p and q such that the point (p,q) is equidistant from (4,0) and (4,0) is

A
p=0
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B
q=0
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C
p+q=0
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D
p+q=8
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Solution

The correct option is A p=0
The distance between points (x1,y1) and (x2,y2) is given by (x2x1)2+(y2y1)2
Since, A(p,q) is equidistant from B(4,0) & C(4,0)
AB=AC
AB=(p+4)2+q2=
AC=(p4)2+q2
(p+4)2+q2=(p4)2+q2
16p=0
p=0

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