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Single Point Continuity

The relation ...

Question

The relation between phase difference (Df) and path difference (Dx) is

[MNR 1995; UPSEAT 1999, 2000]

A

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B

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C

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D

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Solution

The correct option is A

$△ ϕ = \frac{2 π}{λ} △ x$

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Similar questions

Q. The relationship between phase difference

Δ ϕ

and the path difference

Δ x

between two interfering waves is given by
(

λ

A conducting wire of parabolic shape, initially $y = x^{2}$ , is moving with velocity $\to V = V_{0}^i$ in a non-uniform magnetic field $\to B = B_{0} (1 + {(\frac{y}{L})}^{β})^k$ , as shown in figure. If $V_{0}$ , $B_{0}$ , $L$ and $β$ are positive constants and $Δ ϕ$ is the potential difference developed between the ends of the wire, then the correct statement(s) is/are:

ϕ ϵ R

Δ (ϕ) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} sin ϕ & cos ϕ & sin 2 ϕ sin (ϕ + 2 π / 3) & cos (ϕ + 2 π / 3) & sin (2 ϕ + 4 π / 3) sin (ϕ - 2 π / 3) & cos (ϕ - 2 π / 3) & sin (2 ϕ - 2 π / 3) \end{matrix} ∣ ∣ ∣ ∣ ∣

Q. Given below are two statements labelled as Assertion (A) and Reason (R).

Assertion (A) : The charge flown through a cross-section of wire in shape of loop of resistance

R

, when the magnetic flux changes by

Δ ϕ

, is independent of the time in which the flux change is brought.

Reason (R) : For a magnetic flux change of

Δ ϕ

, the charge flown through a cross-section of wire in shape of loop of resistance

R

Q = \frac{Δ ϕ}{R}

Select the most appropriate answer from the options given below.

[

]

The radius of curvature of the path of the charged particle in a uniform magnetic field is directly proportional to

[MNR 1995; UPSEAT 1999, 2000]

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