The relation between the linear velocity and angular velocity is
A
¯ω=¯rׯv
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B
¯v=¯rׯω
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C
¯v=¯ωׯr
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D
¯ω=¯vׯr
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Solution
The correct option is B¯v=¯ωׯr During a circular motion we have the →δθ×→r Dividing by δt we get →δsδt=→δθδt×→r in the derivative form we get this relation as →dsdt=→dθdt×→r or →v=→ω×→r