wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The relation between time and distance is t=αx2+βx, where α and β are constants. The retardation is

A
2αv3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2βv3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2αβv3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

2β2v3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2αv3

dtdx=2αx+βv=12αx+β

a=dvdt=dvdx.dxdt

a=vdvdx=v.2α(2αx+β)2=2α.v.v2=2αv3

Retardation = 2αv3


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Variable Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon