CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The relation between time t and distance x is t=αx2+βx where α and β are constants. Then retardation is:

A
2αv3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2βv3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2αβv3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2β2v3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 2αv3
t=αx2+βx
Differentiating with respect to x we get
dtdx=2αx+βv=12αx+βdvdt=a=2α(2αx+β)3=2αv3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon