The relation between $u, v$ ( u is the object distance and v is the image distance ) and f for mirror is given by:

f = \frac{u v}{u - v}

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f = \frac{2 u \times v}{u + v}

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f = \frac{u \times v}{u + v}

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Solution

The correct option is C $f = \frac{u \times v}{u + v}$
$\frac{1}{u} + \frac{1}{v} = \frac{1}{f}$
or $\frac{u + v}{u v} = \frac{1}{f}$
or $f = \frac{u v}{u + v}$

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Similar questions

The focal length f of a mirror is given by $\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$ where u and v represent object and image distances respectively. The fractional error in 'f' is given by

Q. According to lens formula, the focal length (f) of a lens is given by:
Object distance:

u

Image distance:

v

Q. The object distance

(u)

, image distance

(v)

and the focal length

(f)

of a lens are related as:

Q. The focal length

f

of a mirror is given by

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

, where

u

and

v

represent object and image distances, respectively

Q. By a change of variable

x (u, v) = u v, y (u, v) = v / u

in double integral, the integrand

f (x, y)

changes to

f (u v, v / u) ϕ (u, v)

. Then,

ϕ (u, v)

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The relation between u,v ( u is the object distance and v is the image distance ) and f for mirror is given by:

The correct option is C f=u×vu+v1u+1v=1for u+vuv=1for f=uvu+v

The relation between $u, v$ ( u is the object distance and v is the image distance ) and f for mirror is given by:

The correct option is C $f = \frac{u \times v}{u + v}$
$\frac{1}{u} + \frac{1}{v} = \frac{1}{f}$
or $\frac{u + v}{u v} = \frac{1}{f}$
or $f = \frac{u v}{u + v}$