Question

The relation between voltage sensitivity $\left({\sigma }_v\right)$ and current sensitivity $\left({\sigma }_i\right)$ of a moving coil galvanometer is (resistance of galvanometer is $G$).

• A. $\frac{{\sigma }_i}{G}={\sigma }_v$
• B. $\frac{{\sigma }_v}{G}={\sigma }_i$
• C. $\frac{G}{{\sigma }_v}={\sigma }_i$
• D. None of the above

Answer 1

The correct option is A $\frac{{\sigma }_i}{G}={\sigma }_v$

${\sigma }_i=\frac{\theta }{i}=\frac{\theta }{iG}.G={\sigma }_{v}G\Rightarrow {\sigma }_v=\frac{{\sigma }_i}{G}$.