The relation f is defined by f(x) = {x2,0≤x≤33x,3≤x≤10 and
The relation g is defined by g(x) = {x2,0≤x≤23x,2≤x≤10 Then,
A
'f' is a function and 'g' is not a function
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B
'g' is a function and 'f' is not a function
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C
Both 'f' and 'g' are functions
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D
neither 'f' nor 'g' are functions
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Solution
The correct option is A 'f' is a function and 'g' is not a function Both f and g have multiple definitions at x=3 and x=2 respectively. f(3)=32=9(∵f(x)=x2) Also, f(3)=3×3=9(∵f(x)=3x) f(3) is unique. g(2)=22=4(∵g(x)=x2) Also, g(2)=3×2=6(∵g(x)=3x) g(2) is not unique Hence 'f' is a function but 'g' is not