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Question

The relation P defined from R to R as a P b 1 + ab > 0, for all a, b ϵ R is

A
reflexive only
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B
reflexive and symmetric only
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C
transitive only
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D
equivalence
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Solution

The correct option is B reflexive and symmetric only
Pb1+ab>0

i)Reflexive: a×a for any real value except 0 is positive.Hence 0×0+1>1a×a+1>0

ii)Symmetric: if a×b+1>0 then b×a+1 will also be >0

iii)Not Transitive: a=-2,b=0\Rightarrow -2\times 0+1>0$

b=0,c=40×4+1>0

but a is not related to c a=2,c=42×4+1<0

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