The relation R is defined on the set of natural numbers as {(a,b):a=2b}.
Then R−1 is given by
A
None of these
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B
R−1 is not defined
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C
{(2,1),(4,2),(6,3)…..}
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D
{(1,2),(2,4),(3,6)….}
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Solution
The correct option is D{(1,2),(2,4),(3,6)….} Using (x,y)∈R⇔(y,x)∈R−1,
Here R={(a,b):a=2b} where a,b∈N ⇒R={(2,1),(4,2),(6,3),……}
So, R−1={(1,2),(2,4),(3,6),……}.