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Standard XII

Physics

Relative Velocity in 2D

The relation ...

Question

The relation $t = \sqrt{x} + 3$ describes the position of a particle where x is in meters and t is in seconds. The position, when velocity is zero, is:-

2 m

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4 m

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5 m

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zero

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Solution

The correct option is D zero
$t = \sqrt{x + 3}$
Velocity $= 0$
$t = x^{1 / 2} + 3$
$t - 3 = x^{1 / 2}$
$(t - 3)^{2} = x \frac{d x}{d t} = 2 (t - 3)$
For $v = 0$
$o = 2 t - 6 t = 3 s$

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The relation t=√x+3 describes the position of a particle where x is in meters and t is in seconds. The position, when velocity is zero, is:-

The correct option is D zerot=√x+3Velocity=0t=x1/2+3t−3=x1/2(t−3)2=xdxdt=2(t−3)For v=0o=2t−6t=3s

The relation $t = \sqrt{x} + 3$ describes the position of a particle where x is in meters and t is in seconds. The position, when velocity is zero, is:-

The correct option is D zero
$t = \sqrt{x + 3}$
Velocity $= 0$
$t = x^{1 / 2} + 3$
$t - 3 = x^{1 / 2}$
$(t - 3)^{2} = x \frac{d x}{d t} = 2 (t - 3)$
For $v = 0$
$o = 2 t - 6 t = 3 s$